10-19-2009, 10:45 PM
Ok let's take a look at your formula:
We'll try 5 for both.
Probability of a random person in raid getting targetted 5 times in a row with 5 amount of chases
F(5,5) = .04^(5-1) + .96F(5-1,5) which equals
F(5,5) = .04^(4) + .96F(4,5) which equals
F(5,5) = .00000256 + .96F(4,5)
Now go ahead and finish the equation for me Lorake.
Lorake Wrote:Probability of a random person in raid getting targetted Y times in a row with X amount of chases
F(X,Y) = 0 when Y>X
F(X,Y) = 1 when Y = 1 *Edit: broke my own equation LOL
F(X,Y) = .04^(Y-1) + .96F(X-1,Y)
We'll try 5 for both.
Probability of a random person in raid getting targetted 5 times in a row with 5 amount of chases
F(5,5) = .04^(5-1) + .96F(5-1,5) which equals
F(5,5) = .04^(4) + .96F(4,5) which equals
F(5,5) = .00000256 + .96F(4,5)
Now go ahead and finish the equation for me Lorake.
