It's 4%, AKA the Go Fuck Yourself Post.

[Lorake]

Do some math for me now Roj.

Your case, 5, 5.

Find out the specific combinations of people selected in a 25 man raid, and tell me the probability that selections 1,2,3,4 and 5 are all equal.

Here's a hint - the probability of a single individual being selected 5 times in one go is .04^5

Hmm this looks suspiciously like my earlier post:

The probability of any raid member being targetted "X" times in a row is (1/25)^(X).

I.E.
1 time = (1/25)^(1) = 4%
2 times in a row = (1/25)^(2) = .16%
3 times in a row = (1/25)^(3) = .0064%
4 times in a row = (1/25)^(4) = .000256%

Get raped kid.

Suspicious, but if you think it's .04^5 is your final answer, you're dead wrong. After all there are 25 people and not one person.

You know, sometimes, I forget who I'm talking to. Numero Uno is all that matters, so I suppose one person is the only case that matters, and that's the Roj case.