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+--- Thread: It's 4%, AKA the Go Fuck Yourself Post. (/showthread.php?tid=1373)
Re: It's 4%, AKA the Go Fuck Yourself Post. - Hitshade - 10-20-2009
Lorake Wrote:
I JUST NEED TO STOP DOING TYPOS WHEN PLUGGING AND CHUGGING.
lol omg, this one is gold.
Re: It's 4%, AKA the Go Fuck Yourself Post. - Crazy Diana - 10-20-2009
i googled math fight and got a clip from a shitty show
Re: It's 4%, AKA the Go Fuck Yourself Post. - Hitshade - 10-20-2009
Meanwhile in Korea
Re: It's 4%, AKA the Go Fuck Yourself Post. - Lorake - 10-20-2009
Roj Wrote:Edit: I understand what Lorake is attempting to explain. The chance for a raid member to be targetted the first time by Anub is 4%. The chance for him to be targetted again is also 4%. If a raid member was targetted 99 times in a row, the chance for him to be targetted the 100th time would also be 4%. All of this is pretty obvious. The problem with Lorake is he is by far the most arrogant person I have ever known, so he is trying to back up his explanation by posting bullshit equations which do not work.
Ok here we go with another day of Lorake's copy/paste trash math. Let's look at your latest "equation"
Lorake Wrote:Probability of a random person in raid getting targetted Y times in a row with X amount of chasesI'll use 3 and 5.
F(X,Y) = 0 when Y>X
F(X,Y) = 1 when Y = 1 *Edit: broke my own equation LOL
F(X,Y) = .04^(Y-1) + .96F(X-1,Y)
Probability of a random person in raid getting targetted 3 times in a row with 5 amount of chases (this doesn't even make sense but the equation you copy/pasted had two variables so you went with it)
F(X,Y) = .04^(Y-1) + .96F(X-1,Y)
F(5,3) = .04^(3-1) + .96F(5-1,3)
F(5,3) = .04^(2) + .96F(4,3)
F(5,3) = .0016 + .96F(4,3)
ROFL this is such a joke. Go ahead and finish the equation Lorake.
F(5,3) = .04^(2) + .96F(4,3) = .04^(2) + .96(.04^(2)+ .96F(3,3)) = .04^(2) + .96(.04^(2) + .96(.04^(2) + F(2,3)))
= .04^(2) + .96(.04^(2) + .96(.04^(2))) = .04^2 + .04^2 * .96+ .04^2 * .96^2
Individual's chance
TTTTT = .04^5
TTTTF = .96^1 * .04^4
TTTFT = .96^1 * .04^4
TTTFF = .96^2 * .04^3
TTFTT = no 3btb
TTFTF = no 3btb
TTFFT = no 3btb
TTFFF = no 3btb
TFTTT = .96^1 * .04^4
TFTTF = no 3btb
TFTFT = no 3btb
TFTFF = no 3btb
TFFTT = no 3btb
TFFTF = no 3btb
TFFFT = no 3btb
TFFFF = no 3btb
FTTTT = .96^1 * .04^4
FTTTF = .96^2 * .04^3
FTTFT = no 3btb
FTTFF = no 3btb
FTFTT = no 3btb
FTFTF = no 3btb
FTFFT = no 3btb
FTFFF = no 3btb
FFTTT = .96^2 * .04^3
FFTTF = no 3btb
FFTFT = no 3btb
FFTFF = no 3btb
FFFTT = no 3btb
FFFTF = no 3btb
FFFFT = no 3btb
FFFFF = no 3btb
Sum = .04^5 + 4 * .04^4 * . 96 + 3 * .04^3 * .96 ^ 2
^ Individual case. But we have 25, so multiple
Sum(25) = .04^4 + 4 * .04^3 * . 96 + 3 * .04^2 * .96 ^ 2 =0.004672
F(5,3) = .04^2 + .04^2 * .96 + .04^2 * .96^2 = 0.00461056
A different of .04^3 * .96
Check my numbers and verify I did the sum of the individual and F(X,Y) right. If this is true Roj is right about my formula, and my formula and I have to eat crow on this one, but it still stands Anub has a .04^(X-1) chance of X selecting people in X tries, as my formula has held and matched. My formula holds true for X chases in a row with X chances, and X-1 chases in a row with X chances, which were the two original cases I checked myself before putting this monstrosity up.
And there you go Roj. If you had only given a simple case and not just said NO NO LOL YOU'RE RETARDED and make yourself look like shit, then you could have walked away from this one clean and not looking like a retard bantering nonsense for 8 pages. The first few cases you gave me were shot down, only because you didn't even bother thinking it out. I'm sure if you actually had tried to make sense you could have came up with the case to break it easily, but thanks to your random number generation YOU LUCKED OUT.
Roj Wrote:Edit: I understand what Lorake is attempting to explain. The chance for a raid member to be targetted the first time by Anub is 4%. The chance for him to be targetted again is also 4%. If a raid member was targetted 99 times in a row, the chance for him to be targetted the 100th time would also be 4%. All of this is pretty obvious. The problem with Lorake is he is by far the most arrogant person I have ever known, so he is trying to back up his explanation by posting bullshit equations which do not work.
I LOLed to this one. Roj, if there's ever someone who can be arrogant, it's you. Never willing to admit it's your fault in the process, which is why even though the above equation fails, I'm now going to fix the issue you caused and validate it for 2 BTBs, 5 chases as well as 3 BTBs, 5 chases, just so I am the one who gets to tell you to go fuck yourself in the end.
Re: It's 4%, AKA the Go Fuck Yourself Post. - Lorake - 10-20-2009
So go fuck yourself Roj, have fun with this one.
So problem fixed for now new equation holds under (5,3) as well as the previous cases of (5,4) and (5,5), but hold your breath until I can really test out the case of F(5,2)
Find the probability of Y back to back chases given Anub does X chases
F(X,Y) = 0 when Y>X
F(X,Y) = 1 when Y = 1
F(X,Y) = .04^(Y-1) + .96(F(X-1,Y) +F(X-1, Y+1))
F(5,3) = .04^(2) + .96(F(4,3)+F(4,4)) = .04^(2) + .96(.04^(2)+ .96F(3,3) + .04^3) = .04^(2) + .96(.04^(2) + .96(.04^(2) + F(2,3) + .04^3))
= .04^(2) + .96(.04^(2) + .96(.04^(2)) + .04^3 ) = .04^2 + .04^2 * .96+ .04^2 * .96^2 + .04^3 * .96
Individual's chance (use previous post)
Sum = .04^5 + 4 * .04^4 * . 96 + 3 * .04^3 * .96 ^ 2
^ Individual case. But we have 25, so multiple
Sum(25) = .04^4 + 4 * .04^3 * . 96 + 3 * .04^2 * .96 ^ 2 =0.004672
F(5,3) = .04^2 + .04^2 * .96 + .04^2 * .96^2 + .04^3 * .96 = 0.004672
Eliminating the difference.
The forumula still holds for F(5,4) since F(5,4) = .04^3 + .96(F(4,4) + F(4,5)) = .04^3 + .96F(4,4) = Old algorithm.
I have a problem now. Because the cases of a triple chase of this case are independent, it’s possible to have a double chase occur twice in 5 chases (ROJ, ROJ, LORAKE, LORAKE, ABEC) thus it’s not logical to multiple by 25, since each individual’s chance of a overlap with each other in certain cases. I’ll see if I can get my hands on a C++ program or something to have it calculate the probability of a double chase through raw power. This problem hasn’t been apparent in previous ones since it’s unpossible for two people to have the triple chase occur in 5 chases (UNPOSSIBLE).
Re: It's 4%, AKA the Go Fuck Yourself Post. - Crazy Diana - 10-20-2009
did you grow a white beard and ponder this over a chalkboard too you fucking nerd
Re: It's 4%, AKA the Go Fuck Yourself Post. - Lorake - 10-20-2009
cr4zyd Wrote:did you grow a white beard and ponder this over a chalkboard too you fucking nerd
Yes.
Re: It's 4%, AKA the Go Fuck Yourself Post. - Crazy Diana - 10-20-2009
einstein meets gandalf came to mind
Re: It's 4%, AKA the Go Fuck Yourself Post. - Lorake - 10-20-2009
I cast magic missle at the darkness.
Re: It's 4%, AKA the Go Fuck Yourself Post. - Masex - 10-20-2009
Is there anything worth reading in this thread?